</div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Power PMV @ Jan 5 2004, 04:41 PM)</td></tr><tr><td id='QUOTE'> ok Boner, here is your answer.

OK, let x be the number of casette players and y the number of CD players.
Then we know that:

x&lt;=750
y&lt;=500
2x+5y&lt;=3000 (II)

Profit=4x+7y=4x+10y-3y=2(2x+5y)-3y&lt;=2*3000-3y=6000-3y (from II)
We want the profit to equal its maximum so we make that inequality an equality by saying:
Profit=6000-3y (assuming we are using up all the 3000 hours)
so 2x+5y=3000
Finally to attain the maximum profit we look for the minimum value of y that satisfies our equations.
Since x&lt;=750 then 2x&lt;=1500 and because 2x+5y=3000 we get
5y=3000-2y&gt;=3000-1500=1500 so y&gt;=1500/5=300.
Therefore the minimum value of y we can pick is <span style='font-size:14pt;line-height:100%'>300</span>, and with it our maximum profit becomes 6000-3*300=5100.

Hope that helps
P.S. Send the hentai sites now </td></tr></table><div class='postcolor'>
lol yes sir&#33;